Rewrite \(1+SINB\) in the form \({a}^{3}+{b}^{3}\), where \(a=1\) and \(b=0\).
\[\frac{cosB}{{1}^{3}+{0}^{3}}\times \frac{1+SIN}{COSB}=2SECB\]
Simplify \({1}^{3}\) to \(1\).
\[\frac{cosB}{1+{0}^{3}}\times \frac{1+SIN}{COSB}=2SECB\]
Simplify \({0}^{3}\) to \(0\).
\[\frac{cosB}{1+0}\times \frac{1+SIN}{COSB}=2SECB\]
Simplify \(1+0\) to \(1\).
\[\frac{cosB}{1}\times \frac{1+SIN}{COSB}=2SECB\]
Simplify \(\frac{cosB}{1}\) to \(cosB\).
\[cosB\times \frac{1+SIN}{COSB}=2SECB\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\frac{cosB(1+SIN)}{COSB}=2SECB\]
Rewrite \(1+SIN\) in the form \({a}^{3}+{b}^{3}\), where \(a=1\) and \(b=0\).
\[\frac{cosB({1}^{3}+{0}^{3})}{COSB}=2SECB\]
Simplify \({1}^{3}\) to \(1\).
\[\frac{cosB(1+{0}^{3})}{COSB}=2SECB\]
Simplify \({0}^{3}\) to \(0\).
\[\frac{cosB(1+0)}{COSB}=2SECB\]
Simplify \(1+0\) to \(1\).
\[\frac{cosB\times 1}{COSB}=2SECB\]
Simplify \(cosB\times 1\) to \(cosB\).
\[\frac{cosB}{COSB}=2SECB\]
Since \(\frac{cosB}{COSB}=2SECB\) is false, there is no solution.
[No Solution]
