Variable $x$ cannot be equal to $\frac{1}{5}$ since division by zero is not defined. Multiply both sides of the equation by $15\left(5x-1\right)$, the least common multiple of $3\times 5x-3,5$.
$$5\left(0\times 2x+5\right)=6\left(5x-1\right)$$
Multiply $0$ and $2$ to get $0$.
$$5\left(0x+5\right)=6\left(5x-1\right)$$
Anything times zero gives zero.
$$5\left(0+5\right)=6\left(5x-1\right)$$
Add $0$ and $5$ to get $5$.
$$5\times 5=6\left(5x-1\right)$$
Multiply $5$ and $5$ to get $25$.
$$25=6\left(5x-1\right)$$
Use the distributive property to multiply $6$ by $5x-1$.
$$25=30x-6$$
Swap sides so that all variable terms are on the left hand side.
