$$\frac{0\cdot5y-9}{0\cdot25}=4y-3$$
$y=-16.5$
$$\frac{0.5y}{0.25}+\frac{-9}{0.25}=4y-3$$
$$2y+\frac{-9}{0.25}=4y-3$$
$$2y+\frac{-900}{25}=4y-3$$
$$2y-36=4y-3$$
$$2y-36-4y=-3$$
$$-2y-36=-3$$
$$-2y=-3+36$$
$$-2y=33$$
$$y=\frac{33}{-2}$$
$$y=-\frac{33}{2}$$
Show Solution
Hide Solution