$$\frac{0.1}{c^{2}}=Anti\log(1288); =19.408$$
$c=-\frac{5\sqrt{322}}{322}\approx -0.278639106\text{, }d=19.408$
$c=\frac{5\sqrt{322}}{322}\approx 0.278639106\text{, }d=19.408$
