Question

$$\frac{ 0,23(7)+ \frac{ 43 }{ 450 } }{ 0,5(61)- \frac{ 113 }{ 495 } }$$

Answer

0,INF,150862

Solution


Simplify  \(23\times 7\)  to  \(161\).
\[\frac{0,161+\frac{43}{450}}{0,5\times 61-\frac{113}{495}}\]
Simplify  \(161+\frac{43}{450}\)  to  \(\frac{72493}{450}\).
\[\frac{0,\frac{72493}{450}}{0,5\times 61-\frac{113}{495}}\]
Simplify  \(5\times 61\)  to  \(305\).
\[\frac{0,\frac{72493}{450}}{0,305-\frac{113}{495}}\]
Simplify  \(305-\frac{113}{495}\)  to  \(\frac{150862}{495}\).
\[\frac{0,\frac{72493}{450}}{0,\frac{150862}{495}}\]
Invert and multiply.
\[0,\frac{72493}{450}\times \frac{495}{0},150862\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[0,\frac{72493\times 495}{450\times 0},150862\]
Simplify  \(72493\times 495\)  to  \(35884035\).
\[0,\frac{35884035}{450\times 0},150862\]
Simplify  \(450\times 0\)  to  \(0\).
\[0,\frac{35884035}{0},150862\]
Simplify  \(\frac{35884035}{0}\)  to  \(\infty \).
\[0,\infty ,150862\]