1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 1 } { 1 } + \frac { 1 } { 2 } + \frac { 3 } { 4 }$$

$\frac{9}{4}=2.25$

Divide $1$ by $1$ to get $1$.

$$1+\frac{1}{2}+\frac{3}{4}$$

Convert $1$ to fraction $\frac{2}{2}$.

$$\frac{2}{2}+\frac{1}{2}+\frac{3}{4}$$

Since $\frac{2}{2}$ and $\frac{1}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{2+1}{2}+\frac{3}{4}$$

Add $2$ and $1$ to get $3$.

$$\frac{3}{2}+\frac{3}{4}$$

Least common multiple of $2$ and $4$ is $4$. Convert $\frac{3}{2}$ and $\frac{3}{4}$ to fractions with denominator $4$.

$$\frac{6}{4}+\frac{3}{4}$$

Since $\frac{6}{4}$ and $\frac{3}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{6+3}{4}$$

Add $6$ and $3$ to get $9$.

$$\frac{9}{4}$$

$\frac{3 ^ {2}}{2 ^ {2}} = 2\frac{1}{4} = 2.25$