How to solve (1)/(10)-(1)/(25)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(10)-(1)/(25) | Equatix

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$$\frac{ 1 }{ 10 } - \frac{ 1 }{ 25 }$$

$\frac{3}{50}=0.06$

Least common multiple of $10$ and $25$ is $50$. Convert $\frac{1}{10}$ and $\frac{1}{25}$ to fractions with denominator $50$.

$$\frac{5}{50}-\frac{2}{50}$$

Since $\frac{5}{50}$ and $\frac{2}{50}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-2}{50}$$

Subtract $2$ from $5$ to get $3$.

$$\frac{3}{50}$$

$\frac{3}{2 \cdot 5 ^ {2}} = 0.06$