Solve ( iv ) 1/12, 1/23, 1/5, 1/7, 1/50, 1/9, 1/17 order | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac { 1 } { 12 } , \frac { 1 } { 23 } , \frac { 1 } { 5 } , \frac { 1 } { 7 } , \frac { 1 } { 50 } , \frac { 1 } { 9 } , \frac { 1 } { 17 }$$

Sort

$\frac{1}{50},\frac{1}{23},\frac{1}{17},\frac{1}{12},\frac{1}{9},\frac{1}{7},\frac{1}{5}$

Solution Steps

Least common denominator of the numbers in the list $\frac{1}{12},\frac{1}{23},\frac{1}{5},\frac{1}{7},\frac{1}{50},\frac{1}{9},\frac{1}{17}$ is $2463300$. Convert numbers in the list to fractions with denominator $2463300$.

$$\frac{205275}{2463300},\frac{107100}{2463300},\frac{492660}{2463300},\frac{351900}{2463300},\frac{49266}{2463300},\frac{273700}{2463300},\frac{144900}{2463300}$$

To sort the list, start from a single element $\frac{205275}{2463300}$.

$$\frac{205275}{2463300}$$

Insert $\frac{107100}{2463300}$ to the appropriate location in the new list.

$$\frac{107100}{2463300},\frac{205275}{2463300}$$

Insert $\frac{492660}{2463300}$ to the appropriate location in the new list.

$$\frac{107100}{2463300},\frac{205275}{2463300},\frac{492660}{2463300}$$

Insert $\frac{351900}{2463300}$ to the appropriate location in the new list.

$$\frac{107100}{2463300},\frac{205275}{2463300},\frac{351900}{2463300},\frac{492660}{2463300}$$

Insert $\frac{49266}{2463300}$ to the appropriate location in the new list.

$$\frac{49266}{2463300},\frac{107100}{2463300},\frac{205275}{2463300},\frac{351900}{2463300},\frac{492660}{2463300}$$

Insert $\frac{273700}{2463300}$ to the appropriate location in the new list.

$$\frac{49266}{2463300},\frac{107100}{2463300},\frac{205275}{2463300},\frac{273700}{2463300},\frac{351900}{2463300},\frac{492660}{2463300}$$

Insert $\frac{144900}{2463300}$ to the appropriate location in the new list.

$$\frac{49266}{2463300},\frac{107100}{2463300},\frac{144900}{2463300},\frac{205275}{2463300},\frac{273700}{2463300},\frac{351900}{2463300},\frac{492660}{2463300}$$

Replace the obtained fractions with the initial values.

$$\frac{1}{50},\frac{1}{23},\frac{1}{17},\frac{1}{12},\frac{1}{9},\frac{1}{7},\frac{1}{5}$$

Evaluate

$\frac{1}{12},\frac{1}{23},\frac{1}{5},\frac{1}{7},\frac{1}{50},\frac{1}{9},\frac{1}{17}$