How to solve 1/13 - 3/117

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/13 - 3/117 | Equatix

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$$\frac{1}{13}-\frac{3}{117}$$

$\frac{2}{39}\approx 0.051282051$

Reduce the fraction $\frac{3}{117}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{13}-\frac{1}{39}$$

Least common multiple of $13$ and $39$ is $39$. Convert $\frac{1}{13}$ and $\frac{1}{39}$ to fractions with denominator $39$.

$$\frac{3}{39}-\frac{1}{39}$$

Since $\frac{3}{39}$ and $\frac{1}{39}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-1}{39}$$

Subtract $1$ from $3$ to get $2$.

$$\frac{2}{39}$$

$\frac{2}{3 \cdot 13} = 0.05128205128205128$