How to solve 1/15 + 1 - 9/10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/15 + 1 - 9/10 | Equatix

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Question

$$\frac{1}{15}+1-\frac{9}{10}$$

Evaluate

$\frac{1}{6}\approx 0.166666667$

Solution Steps

Convert $1$ to fraction $\frac{15}{15}$.

$$\frac{1}{15}+\frac{15}{15}-\frac{9}{10}$$

Since $\frac{1}{15}$ and $\frac{15}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{1+15}{15}-\frac{9}{10}$$

Add $1$ and $15$ to get $16$.

$$\frac{16}{15}-\frac{9}{10}$$

Least common multiple of $15$ and $10$ is $30$. Convert $\frac{16}{15}$ and $\frac{9}{10}$ to fractions with denominator $30$.

$$\frac{32}{30}-\frac{27}{30}$$

Since $\frac{32}{30}$ and $\frac{27}{30}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{32-27}{30}$$

Subtract $27$ from $32$ to get $5$.

$$\frac{5}{30}$$

Reduce the fraction $\frac{5}{30}$ to lowest terms by extracting and canceling out $5$.

$$\frac{1}{6}$$

Show Solution

Factor

$\frac{1}{2 \cdot 3} = 0.16666666666666666$