Question

$$\frac{ 1 }{ 2 } \sqrt{ 128 } +3 \sqrt{ 2 } +2 \sqrt{ 72 }$$

Answer

19*sqrt(2)

Solution


Simplify  \(\sqrt{128}\)  to  \(8\sqrt{2}\).
\[\frac{1}{2}\times 8\sqrt{2}+3\sqrt{2}+2\sqrt{72}\]
Simplify  \(\sqrt{72}\)  to  \(6\sqrt{2}\).
\[\frac{1}{2}\times 8\sqrt{2}+3\sqrt{2}+2\times 6\sqrt{2}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{1\times 8\sqrt{2}}{2}+3\sqrt{2}+2\times 6\sqrt{2}\]
Simplify  \(1\times 8\sqrt{2}\)  to  \(8\sqrt{2}\).
\[\frac{8\sqrt{2}}{2}+3\sqrt{2}+2\times 6\sqrt{2}\]
Simplify  \(2\times 6\sqrt{2}\)  to  \(12\sqrt{2}\).
\[\frac{8\sqrt{2}}{2}+3\sqrt{2}+12\sqrt{2}\]
Simplify.
\[19\sqrt{2}\]

Decimal Form: 26.870058