$$\frac{1}{2}(4m-8n)+4(2m-\frac{1}{4}n)=$$
$10m-5n$
$$\frac{1}{2}\times 4m+\frac{1}{2}\left(-8\right)n+4\left(2m-\frac{1}{4}n\right)$$
$$\frac{4}{2}m+\frac{1}{2}\left(-8\right)n+4\left(2m-\frac{1}{4}n\right)$$
$$2m+\frac{1}{2}\left(-8\right)n+4\left(2m-\frac{1}{4}n\right)$$
$$2m+\frac{-8}{2}n+4\left(2m-\frac{1}{4}n\right)$$
$$2m-4n+4\left(2m-\frac{1}{4}n\right)$$
$$2m-4n+8m+4\left(-\frac{1}{4}\right)n$$
$$2m-4n+8m-n$$
$$10m-4n-n$$
$$10m-5n$$
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