Question

$$\frac{1}{2}\times\frac{1}{4}+\frac{2}{3}[\frac{4}{5}-\frac{7}{8}]; \frac{5}{2}\div2\times\frac{5}{2}$$

Answer

1/8+(2*[4)/15-7/8];5/2/2*5/2

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
(1*1)/(2*4)+2/3*\(\frac{4}{5}-\frac{7}{8}\);5/2/2*5/2
Simplify  \(1\times 1\)  to  \(1\).
1/(2*4)+2/3*\(\frac{4}{5}-\frac{7}{8}\);5/2/2*5/2
Simplify  \(2\times 4\)  to  \(8\).
1/8+2/3*\(\frac{4}{5}-\frac{7}{8}\);5/2/2*5/2
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
1/8+(2*\(4\);5/2/2*5/2
Simplify  \(3\times 5\)  to  \(15\).
1/8+(2*\(4\);5/2/2*5/2