How to solve (1)/(20)+(1)/(40)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(20)+(1)/(40) | Equatix

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$$\frac{ 1 }{ 20 } + \frac{ 1 }{ 40 }$$

$\frac{3}{40}=0.075$

Least common multiple of $20$ and $40$ is $40$. Convert $\frac{1}{20}$ and $\frac{1}{40}$ to fractions with denominator $40$.

$$\frac{2}{40}+\frac{1}{40}$$

Since $\frac{2}{40}$ and $\frac{1}{40}$ have the same denominator, add them by adding their numerators.

$$\frac{2+1}{40}$$

Add $2$ and $1$ to get $3$.

$$\frac{3}{40}$$

$\frac{3}{2 ^ {3} \cdot 5} = 0.075$