1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1 3 | Equatix - Math Solver

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$\frac { 1 } { 24 } - \frac { 1 } { 6 } - \frac { 6 } { 3 } + \frac { 1 } { 6 } + 6 \frac { 2 } { 2 } }$$

Evaluate

$\frac{121}{24}\approx 5.041666667$

Solution Steps

Least common multiple of $24$ and $6$ is $24$. Convert $\frac{1}{24}$ and $\frac{1}{6}$ to fractions with denominator $24$.

$$\frac{1}{24}-\frac{4}{24}-\frac{6}{3}+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Since $\frac{1}{24}$ and $\frac{4}{24}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-4}{24}-\frac{6}{3}+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Subtract $4$ from $1$ to get $-3$.

$$\frac{-3}{24}-\frac{6}{3}+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Reduce the fraction $\frac{-3}{24}$ to lowest terms by extracting and canceling out $3$.

$$-\frac{1}{8}-\frac{6}{3}+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Divide $6$ by $3$ to get $2$.

$$-\frac{1}{8}-2+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Convert $2$ to fraction $\frac{16}{8}$.

$$-\frac{1}{8}-\frac{16}{8}+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Since $-\frac{1}{8}$ and $\frac{16}{8}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-16}{8}+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Subtract $16$ from $-1$ to get $-17$.

$$-\frac{17}{8}+\frac{1}{6}+\frac{6\times 2+2}{2}$$

Least common multiple of $8$ and $6$ is $24$. Convert $-\frac{17}{8}$ and $\frac{1}{6}$ to fractions with denominator $24$.

$$-\frac{51}{24}+\frac{4}{24}+\frac{6\times 2+2}{2}$$

Since $-\frac{51}{24}$ and $\frac{4}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{-51+4}{24}+\frac{6\times 2+2}{2}$$

Add $-51$ and $4$ to get $-47$.

$$-\frac{47}{24}+\frac{6\times 2+2}{2}$$

Multiply $6$ and $2$ to get $12$.

$$-\frac{47}{24}+\frac{12+2}{2}$$

Add $12$ and $2$ to get $14$.

$$-\frac{47}{24}+\frac{14}{2}$$

Divide $14$ by $2$ to get $7$.

$$-\frac{47}{24}+7$$

Convert $7$ to fraction $\frac{168}{24}$.

$$-\frac{47}{24}+\frac{168}{24}$$

Since $-\frac{47}{24}$ and $\frac{168}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{-47+168}{24}$$

Add $-47$ and $168$ to get $121$.

$$\frac{121}{24}$$

Show Solution

Factor

$\frac{11 ^ {2}}{2 ^ {3} \cdot 3} = 5\frac{1}{24} = 5.041666666666667$