How to solve (1)/(3(x)^(3))-9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(3(x)^(3))-9 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{ 1 }{ 3 { x }^{ 3 } } -9$$

$-9+\frac{1}{3x^{3}}$

To add or subtract expressions, expand them to make their denominators the same. Multiply $9$ times $\frac{3x^{3}}{3x^{3}}$.

$$\frac{1}{3x^{3}}-\frac{9\times 3x^{3}}{3x^{3}}$$

Since $\frac{1}{3x^{3}}$ and $\frac{9\times 3x^{3}}{3x^{3}}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-9\times 3x^{3}}{3x^{3}}$$

Do the multiplications in $1-9\times 3x^{3}$.

$$\frac{1-27x^{3}}{3x^{3}}$$

$-\frac{\frac{1}{3}\left(3x-1\right)\left(9x^{2}+3x+1\right)}{x^{3}}$