$$\frac{ 1 }{ 3 } { \left( \log ( x-1 ) \right) }^{ 3 } + \frac{ 10 }{ 9 } \log ( x+1 ) - \frac{ 1 }{ 9 } \log ( x+1 )$$
$\frac{\left(\log_{10}\left(x-1\right)\right)^{3}+3\log_{10}\left(x+1\right)}{3}$
$$\frac{3\left(\log_{10}\left(x-1\right)\right)^{3}+10\log_{10}\left(x+1\right)-\log_{10}\left(x+1\right)}{9}$$
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$\frac{\log(x-1)^{3}}{3}+\log(x+1)$
