$$\frac{ 1 }{ 3 } < \frac{ 40 }{ 90 } < \frac{ 4 }{ 5 }$$
$\text{true}$
$$\frac{1}{3}<\frac{4}{9}\text{ and }\frac{40}{90}<\frac{4}{5}$$
$$\frac{3}{9}<\frac{4}{9}\text{ and }\frac{40}{90}<\frac{4}{5}$$
$$\text{true}\text{ and }\frac{40}{90}<\frac{4}{5}$$
$$\text{true}\text{ and }\frac{4}{9}<\frac{4}{5}$$
$$\text{true}\text{ and }\frac{20}{45}<\frac{36}{45}$$
$$\text{true}\text{ and }\text{true}$$
$$\text{true}$$
Show Solution
Hide Solution
