How to solve b . 1/3; 9/4 of

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve b . 1/3; 9/4 of | Equatix

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$$\frac { 1 } { 3 } \frac { 9 } { 4 } =$$

$\frac{3}{4}=0.75$

Multiply $\frac{1}{3}$ times $\frac{9}{4}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 9}{3\times 4}$$

Do the multiplications in the fraction $\frac{1\times 9}{3\times 4}$.

$$\frac{9}{12}$$

Reduce the fraction $\frac{9}{12}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{4}$$

$\frac{3}{2 ^ {2}} = 0.75$