$$\frac { 1 } { 3 } - ( \frac { - 5 } { 6 } ) = ( \frac { - 5 } { 6 } ) - \frac { 1 } { 3 }$$
$\text{false}$
$$\frac{1}{3}-\left(-\frac{5}{6}\right)=\frac{-5}{6}-\frac{1}{3}$$
$$\frac{1}{3}+\frac{5}{6}=\frac{-5}{6}-\frac{1}{3}$$
$$\frac{2}{6}+\frac{5}{6}=\frac{-5}{6}-\frac{1}{3}$$
$$\frac{2+5}{6}=\frac{-5}{6}-\frac{1}{3}$$
$$\frac{7}{6}=\frac{-5}{6}-\frac{1}{3}$$
$$\frac{7}{6}=-\frac{5}{6}-\frac{1}{3}$$
$$\frac{7}{6}=-\frac{5}{6}-\frac{2}{6}$$
$$\frac{7}{6}=\frac{-5-2}{6}$$
$$\frac{7}{6}=-\frac{7}{6}$$
$$\text{false}$$
Show Solution
Hide Solution