$$\frac { 1 } { 3 } ( x - 2 ) - \frac { 1 } { 2 } ( x - 1 ) = \frac { 5 } { 6 } ( x + 2 )$$
$x = -\frac{11}{6} = -1\frac{5}{6} \approx -1.833333333$
$$\frac{1}{3}x+\frac{1}{3}\left(-2\right)-\frac{1}{2}\left(x-1\right)=\frac{5}{6}\left(x+2\right)$$
$$\frac{1}{3}x+\frac{-2}{3}-\frac{1}{2}\left(x-1\right)=\frac{5}{6}\left(x+2\right)$$
$$\frac{1}{3}x-\frac{2}{3}-\frac{1}{2}\left(x-1\right)=\frac{5}{6}\left(x+2\right)$$
$$\frac{1}{3}x-\frac{2}{3}-\frac{1}{2}x-\frac{1}{2}\left(-1\right)=\frac{5}{6}\left(x+2\right)$$
$$\frac{1}{3}x-\frac{2}{3}-\frac{1}{2}x+\frac{1}{2}=\frac{5}{6}\left(x+2\right)$$
$$-\frac{1}{6}x-\frac{2}{3}+\frac{1}{2}=\frac{5}{6}\left(x+2\right)$$
$$-\frac{1}{6}x-\frac{4}{6}+\frac{3}{6}=\frac{5}{6}\left(x+2\right)$$
$$-\frac{1}{6}x+\frac{-4+3}{6}=\frac{5}{6}\left(x+2\right)$$
$$-\frac{1}{6}x-\frac{1}{6}=\frac{5}{6}\left(x+2\right)$$
$$-\frac{1}{6}x-\frac{1}{6}=\frac{5}{6}x+\frac{5}{6}\times 2$$
$$-\frac{1}{6}x-\frac{1}{6}=\frac{5}{6}x+\frac{5\times 2}{6}$$
$$-\frac{1}{6}x-\frac{1}{6}=\frac{5}{6}x+\frac{10}{6}$$
$$-\frac{1}{6}x-\frac{1}{6}=\frac{5}{6}x+\frac{5}{3}$$
$$-\frac{1}{6}x-\frac{1}{6}-\frac{5}{6}x=\frac{5}{3}$$
$$-x-\frac{1}{6}=\frac{5}{3}$$
$$-x=\frac{5}{3}+\frac{1}{6}$$
$$-x=\frac{10}{6}+\frac{1}{6}$$
$$-x=\frac{10+1}{6}$$
$$-x=\frac{11}{6}$$
$$x=-\frac{11}{6}$$
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