$$\frac{1}{3}(x-3)+\frac{2}{3}=\frac{4x-3}{6}$$
$x=\frac{1}{2}=0.5$
$$2\left(x-3\right)+4=4x-3$$
$$2x-6+4=4x-3$$
$$2x-2=4x-3$$
$$2x-2-4x=-3$$
$$-2x-2=-3$$
$$-2x=-3+2$$
$$-2x=-1$$
$$x=\frac{-1}{-2}$$
$$x=\frac{1}{2}$$
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