How to solve (1)/(3)+(1)/(35)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(3)+(1)/(35) | Equatix

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$$\frac{ 1 }{ 3 } + \frac{ 1 }{ 35 }$$

$\frac{38}{105}\approx 0.361904762$

Least common multiple of $3$ and $35$ is $105$. Convert $\frac{1}{3}$ and $\frac{1}{35}$ to fractions with denominator $105$.

$$\frac{35}{105}+\frac{3}{105}$$

Since $\frac{35}{105}$ and $\frac{3}{105}$ have the same denominator, add them by adding their numerators.

$$\frac{35+3}{105}$$

Add $35$ and $3$ to get $38$.

$$\frac{38}{105}$$

$\frac{2 \cdot 19}{3 \cdot 5 \cdot 7} = 0.3619047619047619$