How to solve (1)/(3)+(2)/(5)-1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(3)+(2)/(5)-1 | Equatix

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$$\frac{ 1 }{ 3 } + \frac{ 2 }{ 5 } -1$$

$-\frac{4}{15}\approx -0.266666667$

Least common multiple of $3$ and $5$ is $15$. Convert $\frac{1}{3}$ and $\frac{2}{5}$ to fractions with denominator $15$.

$$\frac{5}{15}+\frac{6}{15}-1$$

Since $\frac{5}{15}$ and $\frac{6}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{5+6}{15}-1$$

Add $5$ and $6$ to get $11$.

$$\frac{11}{15}-1$$

Convert $1$ to fraction $\frac{15}{15}$.

$$\frac{11}{15}-\frac{15}{15}$$

Since $\frac{11}{15}$ and $\frac{15}{15}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{11-15}{15}$$

Subtract $15$ from $11$ to get $-4$.

$$-\frac{4}{15}$$

$-\frac{4}{15} = -0.26666666666666666$