How to solve (1)/(3)+(2)/(5)+2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(3)+(2)/(5)+2 | Equatix

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$$\frac{ 1 }{ 3 } + \frac{ 2 }{ 5 } +2$$

$\frac{41}{15}\approx 2.733333333$

Least common multiple of $3$ and $5$ is $15$. Convert $\frac{1}{3}$ and $\frac{2}{5}$ to fractions with denominator $15$.

$$\frac{5}{15}+\frac{6}{15}+2$$

Since $\frac{5}{15}$ and $\frac{6}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{5+6}{15}+2$$

Add $5$ and $6$ to get $11$.

$$\frac{11}{15}+2$$

Convert $2$ to fraction $\frac{30}{15}$.

$$\frac{11}{15}+\frac{30}{15}$$

Since $\frac{11}{15}$ and $\frac{30}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{11+30}{15}$$

Add $11$ and $30$ to get $41$.

$$\frac{41}{15}$$

$\frac{41}{3 \cdot 5} = 2\frac{11}{15} = 2.7333333333333334$