$$\frac{ 1 }{ 3 } |x-1|- \frac{ 2 }{ 5 } > 1$$
$\frac{|x-1|}{3}-\frac{2}{5}>1$
$x\in \left(-\infty,-\frac{16}{5}\right)\cup \left(\frac{26}{5},\infty\right)$
