$$\frac{ 1 }{ 3 } x+ \frac{ 1 }{ 4 } = \frac{ 2 }{ 5 } (x- \frac{ 3 }{ 4 } )$$
$x = \frac{33}{4} = 8\frac{1}{4} = 8.25$
$$\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x+\frac{2}{5}\left(-\frac{3}{4}\right)$$
$$\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x+\frac{2\left(-3\right)}{5\times 4}$$
$$\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x+\frac{-6}{20}$$
$$\frac{1}{3}x+\frac{1}{4}=\frac{2}{5}x-\frac{3}{10}$$
$$\frac{1}{3}x+\frac{1}{4}-\frac{2}{5}x=-\frac{3}{10}$$
$$-\frac{1}{15}x+\frac{1}{4}=-\frac{3}{10}$$
$$-\frac{1}{15}x=-\frac{3}{10}-\frac{1}{4}$$
$$-\frac{1}{15}x=-\frac{6}{20}-\frac{5}{20}$$
$$-\frac{1}{15}x=\frac{-6-5}{20}$$
$$-\frac{1}{15}x=-\frac{11}{20}$$
$$x=-\frac{11}{20}\left(-15\right)$$
$$x=\frac{-11\left(-15\right)}{20}$$
$$x=\frac{165}{20}$$
$$x=\frac{33}{4}$$
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