$$\frac{ 1 }{ 3 } x+ \frac{ 3 }{ 2 } = \frac{ 8 }{ 3 } x+ \frac{ 4 }{ 5 }$$
$x=\frac{3}{10}=0.3$
$$\frac{1}{3}x+\frac{3}{2}-\frac{8}{3}x=\frac{4}{5}$$
$$-\frac{7}{3}x+\frac{3}{2}=\frac{4}{5}$$
$$-\frac{7}{3}x=\frac{4}{5}-\frac{3}{2}$$
$$-\frac{7}{3}x=\frac{8}{10}-\frac{15}{10}$$
$$-\frac{7}{3}x=\frac{8-15}{10}$$
$$-\frac{7}{3}x=-\frac{7}{10}$$
$$x=-\frac{7}{10}\left(-\frac{3}{7}\right)$$
$$x=\frac{-7\left(-3\right)}{10\times 7}$$
$$x=\frac{21}{70}$$
$$x=\frac{3}{10}$$
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