$$[ \frac { 1 } { 4 } a - \frac { 1 } { 2 } b + 1 ] ^ { 2 }$$
$\frac{\left(a-2b+4\right)^{2}}{16}$
$$\frac{1}{16}a^{2}-\frac{1}{4}ab+\frac{1}{2}a+\frac{1}{4}b^{2}-b+1$$
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$-\frac{ab}{4}+\frac{a^{2}}{16}+\frac{b^{2}}{4}+\frac{a}{2}-b+1$
