$$\frac{1}{4-\sqrt{3}}$$
$\frac{\sqrt{3}+4}{13}\approx 0.440926985$
$$\frac{4+\sqrt{3}}{\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right)}$$
$$\frac{4+\sqrt{3}}{4^{2}-\left(\sqrt{3}\right)^{2}}$$
$$\frac{4+\sqrt{3}}{16-3}$$
$$\frac{4+\sqrt{3}}{13}$$
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