$$\frac{1}{4+\sqrt{3}}$$
$\frac{4-\sqrt{3}}{13}\approx 0.17445763$
$$\frac{4-\sqrt{3}}{\left(4+\sqrt{3}\right)\left(4-\sqrt{3}\right)}$$
$$\frac{4-\sqrt{3}}{4^{2}-\left(\sqrt{3}\right)^{2}}$$
$$\frac{4-\sqrt{3}}{16-3}$$
$$\frac{4-\sqrt{3}}{13}$$
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