How to solve 1/40 + 1/60 = 1/x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/40 + 1/60 = 1/x | Equatix

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Question

$$\frac{1}{40}+\frac{1}{60}=\frac{1}{x}$$

Solve for x

$x=24$

Steps for Solving Linear Equation

Variable $x$ cannot be equal to $0$ since division by zero is not defined. Multiply both sides of the equation by $120x$, the least common multiple of $40,60,x$.

$$120x\times \frac{1}{40}+120x\times \frac{1}{60}=120$$

Multiply $120$ and $\frac{1}{40}$ to get $\frac{120}{40}$.

$$\frac{120}{40}x+120x\times \frac{1}{60}=120$$

Divide $120$ by $40$ to get $3$.

$$3x+120x\times \frac{1}{60}=120$$

Multiply $120$ and $\frac{1}{60}$ to get $\frac{120}{60}$.

$$3x+\frac{120}{60}x=120$$

Divide $120$ by $60$ to get $2$.

$$3x+2x=120$$

Combine $3x$ and $2x$ to get $5x$.

$$5x=120$$

Divide both sides by $5$.

$$x=\frac{120}{5}$$

Divide $120$ by $5$ to get $24$.

$$x=24$$

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