How to solve 1/45 * 9/39

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/45 * 9/39 | Equatix

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$$\frac{1}{45}\times\frac{9}{39}$$

$\frac{1}{195}\approx 0.005128205$

Reduce the fraction $\frac{9}{39}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{45}\times \frac{3}{13}$$

Multiply $\frac{1}{45}$ times $\frac{3}{13}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{45\times 13}$$

Do the multiplications in the fraction $\frac{1\times 3}{45\times 13}$.

$$\frac{3}{585}$$

Reduce the fraction $\frac{3}{585}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{195}$$

$\frac{1}{3 \cdot 5 \cdot 13} = 0.005128205128205128$