$$\frac { 1 } { 5 } 10 g =$$
$2g$
$$\frac{10}{5}g$$
$$2g$$
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$2$
$$\frac{\mathrm{d}}{\mathrm{d}g}(\frac{10}{5}g)$$
$$\frac{\mathrm{d}}{\mathrm{d}g}(2g)$$
$$2g^{1-1}$$
$$2g^{0}$$
$$2\times 1$$
$$2$$
