$$\frac { 1 } { 5 } 225 , 3 \frac { 1 } { 2 }$$
$\frac{7}{2},45$
$$sort(\frac{225}{5},\frac{3\times 2+1}{2})$$
$$sort(45,\frac{3\times 2+1}{2})$$
$$sort(45,\frac{6+1}{2})$$
$$sort(45,\frac{7}{2})$$
$$45,\frac{7}{2}$$
$$45$$
$$\frac{7}{2},45$$
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$45,\frac{7}{2}$