$$\frac { 1 } { 5 } 80 g =$$
$16g$
$$\frac{80}{5}g$$
$$16g$$
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$16$
$$\frac{\mathrm{d}}{\mathrm{d}g}(\frac{80}{5}g)$$
$$\frac{\mathrm{d}}{\mathrm{d}g}(16g)$$
$$16g^{1-1}$$
$$16g^{0}$$
$$16\times 1$$
$$16$$
