How to solve 1/6 - 1/12 + 1/18

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/6 - 1/12 + 1/18 | Equatix

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$$\frac{1}{6}-\frac{1}{12}+\frac{1}{18}$$

$\frac{5}{36}\approx 0.138888889$

Least common multiple of $6$ and $12$ is $12$. Convert $\frac{1}{6}$ and $\frac{1}{12}$ to fractions with denominator $12$.

$$\frac{2}{12}-\frac{1}{12}+\frac{1}{18}$$

Since $\frac{2}{12}$ and $\frac{1}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-1}{12}+\frac{1}{18}$$

Subtract $1$ from $2$ to get $1$.

$$\frac{1}{12}+\frac{1}{18}$$

Least common multiple of $12$ and $18$ is $36$. Convert $\frac{1}{12}$ and $\frac{1}{18}$ to fractions with denominator $36$.

$$\frac{3}{36}+\frac{2}{36}$$

Since $\frac{3}{36}$ and $\frac{2}{36}$ have the same denominator, add them by adding their numerators.

$$\frac{3+2}{36}$$

Add $3$ and $2$ to get $5$.

$$\frac{5}{36}$$

$\frac{5}{2 ^ {2} \cdot 3 ^ {2}} = 0.1388888888888889$