$$\frac{1}{6}-\frac{18}{12}-\frac{21}{9}+\frac{41}{3}$$
$10$
$$\frac{1}{6}-\frac{3}{2}-\frac{21}{9}+\frac{41}{3}$$
$$\frac{1}{6}-\frac{9}{6}-\frac{21}{9}+\frac{41}{3}$$
$$\frac{1-9}{6}-\frac{21}{9}+\frac{41}{3}$$
$$\frac{-8}{6}-\frac{21}{9}+\frac{41}{3}$$
$$-\frac{4}{3}-\frac{21}{9}+\frac{41}{3}$$
$$-\frac{4}{3}-\frac{7}{3}+\frac{41}{3}$$
$$\frac{-4-7}{3}+\frac{41}{3}$$
$$-\frac{11}{3}+\frac{41}{3}$$
$$\frac{-11+41}{3}$$
$$\frac{30}{3}$$
$$10$$
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$2\times 5$
