How to solve (1)/(6)-(4)/(15)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(6)-(4)/(15) | Equatix

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$$\frac{ 1 }{ 6 } - \frac{ 4 }{ 15 }$$

$-\frac{1}{10}=-0.1$

Least common multiple of $6$ and $15$ is $30$. Convert $\frac{1}{6}$ and $\frac{4}{15}$ to fractions with denominator $30$.

$$\frac{5}{30}-\frac{8}{30}$$

Since $\frac{5}{30}$ and $\frac{8}{30}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-8}{30}$$

Subtract $8$ from $5$ to get $-3$.

$$\frac{-3}{30}$$

Reduce the fraction $\frac{-3}{30}$ to lowest terms by extracting and canceling out $3$.

$$-\frac{1}{10}$$

$-\frac{1}{10} = -0.1$