How to solve 1/6 + 5/8 - 7/12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/6 + 5/8 - 7/12 | Equatix

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$$\frac{1}{6}+\frac{5}{8}-\frac{7}{12}$$

$\frac{5}{24}\approx 0.208333333$

Least common multiple of $6$ and $8$ is $24$. Convert $\frac{1}{6}$ and $\frac{5}{8}$ to fractions with denominator $24$.

$$\frac{4}{24}+\frac{15}{24}-\frac{7}{12}$$

Since $\frac{4}{24}$ and $\frac{15}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{4+15}{24}-\frac{7}{12}$$

Add $4$ and $15$ to get $19$.

$$\frac{19}{24}-\frac{7}{12}$$

Least common multiple of $24$ and $12$ is $24$. Convert $\frac{19}{24}$ and $\frac{7}{12}$ to fractions with denominator $24$.

$$\frac{19}{24}-\frac{14}{24}$$

Since $\frac{19}{24}$ and $\frac{14}{24}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-14}{24}$$

Subtract $14$ from $19$ to get $5$.

$$\frac{5}{24}$$

$\frac{5}{2 ^ {3} \cdot 3} = 0.20833333333333334$