Question

$$\frac{1}{6\times10}+\frac{1}{4\times10}-\frac{1}{6\times4}=\vec{m}$$

Answer

v=236/(e*c*m)

Solution


Simplify  \(16\times 10\)  to  \(160\).
\[160+14\times 10-16\times 4=vecm\]
Simplify  \(14\times 10\)  to  \(140\).
\[160+140-16\times 4=vecm\]
Simplify  \(16\times 4\)  to  \(64\).
\[160+140-64=vecm\]
Simplify  \(160+140\)  to  \(300\).
\[300-64=vecm\]
Simplify  \(300-64\)  to  \(236\).
\[236=vecm\]
Divide both sides by \(e\).
\[\frac{236}{e}=vcm\]
Divide both sides by \(c\).
\[\frac{\frac{236}{e}}{c}=vm\]
Simplify  \(\frac{\frac{236}{e}}{c}\)  to  \(\frac{236}{ec}\).
\[\frac{236}{ec}=vm\]
Divide both sides by \(m\).
\[\frac{\frac{236}{ec}}{m}=v\]
Simplify  \(\frac{\frac{236}{ec}}{m}\)  to  \(\frac{236}{ecm}\).
\[\frac{236}{ecm}=v\]
Switch sides.
\[v=\frac{236}{ecm}\]