Solve 1/8 * 3 ^ - 3 = 1/(2 ^ 3); *3^ -3 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{1}{8}\times3^{-3}=\frac{1}{2^{3}}; \times3^{-3}$$

Verify

$\text{false}$

Solution Steps

Calculate $3$ to the power of $-3$ and get $\frac{1}{27}$.

$$\frac{1}{8}\times \frac{1}{27}=\frac{1}{2^{3}}$$

Multiply $\frac{1}{8}$ and $\frac{1}{27}$ to get $\frac{1}{216}$.

$$\frac{1}{216}=\frac{1}{2^{3}}$$

Calculate $2$ to the power of $3$ and get $8$.

$$\frac{1}{216}=\frac{1}{8}$$

Least common multiple of $216$ and $8$ is $216$. Convert $\frac{1}{216}$ and $\frac{1}{8}$ to fractions with denominator $216$.

$$\frac{1}{216}=\frac{27}{216}$$

Compare $\frac{1}{216}$ and $\frac{27}{216}$.

$$\text{false}$$