How to solve 1/9 - 2/27 + 3/81

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/9 - 2/27 + 3/81 | Equatix

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$$\frac{1}{9}-\frac{2}{27}+\frac{3}{81}$$

$\frac{2}{27}\approx 0.074074074$

Least common multiple of $9$ and $27$ is $27$. Convert $\frac{1}{9}$ and $\frac{2}{27}$ to fractions with denominator $27$.

$$\frac{3}{27}-\frac{2}{27}+\frac{3}{81}$$

Since $\frac{3}{27}$ and $\frac{2}{27}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-2}{27}+\frac{3}{81}$$

Subtract $2$ from $3$ to get $1$.

$$\frac{1}{27}+\frac{3}{81}$$

Reduce the fraction $\frac{3}{81}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{27}+\frac{1}{27}$$

Since $\frac{1}{27}$ and $\frac{1}{27}$ have the same denominator, add them by adding their numerators.

$$\frac{1+1}{27}$$

Add $1$ and $1$ to get $2$.

$$\frac{2}{27}$$

$\frac{2}{3 ^ {3}} = 0.07407407407407407$