How to solve (1)/(9)+(7)/(8)=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1)/(9)+(7)/(8)= | Equatix

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$$\frac{ 1 }{ 9 } + \frac{ 7 }{ 8 } =$$

$\frac{71}{72}\approx 0.986111111$

Least common multiple of $9$ and $8$ is $72$. Convert $\frac{1}{9}$ and $\frac{7}{8}$ to fractions with denominator $72$.

$$\frac{8}{72}+\frac{63}{72}$$

Since $\frac{8}{72}$ and $\frac{63}{72}$ have the same denominator, add them by adding their numerators.

$$\frac{8+63}{72}$$

Add $8$ and $63$ to get $71$.

$$\frac{71}{72}$$

$\frac{71}{2 ^ {3} \cdot 3 ^ {2}} = 0.9861111111111112$