How to solve e ) 68 68 a b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve e ) 68 68 a b | Equatix

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Question

$$\frac { 1 } { b ^ { 0 } c ^ { 0 } } d ^ { 1 } =$$

Evaluate

$d$

Solution Steps

Calculate $b$ to the power of $0$ and get $1$.

$$\frac{1}{1c^{0}}d^{1}$$

Calculate $c$ to the power of $0$ and get $1$.

$$\frac{1}{1\times 1}d^{1}$$

Multiply $1$ and $1$ to get $1$.

$$\frac{1}{1}d^{1}$$

Anything divided by one gives itself.

$$1d^{1}$$

Calculate $d$ to the power of $1$ and get $d$.

$$1d$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$d$$

Show Solution

Differentiate w.r.t. d

$1$

Steps Using Definition of a Derivative

Calculate $b$ to the power of $0$ and get $1$.

$$\frac{\mathrm{d}}{\mathrm{d}d}(\frac{1}{1c^{0}}d^{1})$$

Calculate $c$ to the power of $0$ and get $1$.

$$\frac{\mathrm{d}}{\mathrm{d}d}(\frac{1}{1\times 1}d^{1})$$

Multiply $1$ and $1$ to get $1$.

$$\frac{\mathrm{d}}{\mathrm{d}d}(\frac{1}{1}d^{1})$$

Anything divided by one gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}d}(1d^{1})$$

Calculate $d$ to the power of $1$ and get $d$.

$$\frac{\mathrm{d}}{\mathrm{d}d}(1d)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$d^{1-1}$$

Subtract $1$ from $1$.

$$d^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$