How to solve -20 -15-10 -5 0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve -20 -15-10 -5 0 | Equatix

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Question

$$\frac { 1 } { - 20 } - 15 \quad - 10 \quad - 5$$

Evaluate

$-\frac{601}{20}=-30.05$

Solution Steps

Fraction $\frac{1}{-20}$ can be rewritten as $-\frac{1}{20}$ by extracting the negative sign.

$$-\frac{1}{20}-15-10-5$$

Convert $15$ to fraction $\frac{300}{20}$.

$$-\frac{1}{20}-\frac{300}{20}-10-5$$

Since $-\frac{1}{20}$ and $\frac{300}{20}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-300}{20}-10-5$$

Subtract $300$ from $-1$ to get $-301$.

$$-\frac{301}{20}-10-5$$

Convert $10$ to fraction $\frac{200}{20}$.

$$-\frac{301}{20}-\frac{200}{20}-5$$

Since $-\frac{301}{20}$ and $\frac{200}{20}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-301-200}{20}-5$$

Subtract $200$ from $-301$ to get $-501$.

$$-\frac{501}{20}-5$$

Convert $5$ to fraction $\frac{100}{20}$.

$$-\frac{501}{20}-\frac{100}{20}$$

Since $-\frac{501}{20}$ and $\frac{100}{20}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-501-100}{20}$$

Subtract $100$ from $-501$ to get $-601$.

$$-\frac{601}{20}$$

Show Solution

Factor

$-\frac{601}{20} = -30\frac{1}{20} = -30.05$