1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 1 } { ( 7 ) ^ { 2 } } 7 \times 7 \times \frac { 1 } { 28 }$$

$\frac{1}{28}\approx 0.035714286$

Calculate $7$ to the power of $2$ and get $49$.

$$\frac{1}{49}\times 7\times 7\times \frac{1}{28}$$

Multiply $\frac{1}{49}$ and $7$ to get $\frac{7}{49}$.

$$\frac{7}{49}\times 7\times \frac{1}{28}$$

Reduce the fraction $\frac{7}{49}$ to lowest terms by extracting and canceling out $7$.

$$\frac{1}{7}\times 7\times \frac{1}{28}$$

Cancel out $7$ and $7$.

$$\frac{1}{28}$$

$\frac{1}{2 ^ {2} \cdot 7} = 0.03571428571428571$