Question

$$\frac{1}{(7)^{v}}\times7\times7\times\frac{1}{28}$$

Answer

$$7/(4*7^v)$$

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{1\times 7\times 7\times 1}{{7}^{v}\times 28}\]
Simplify  \(1\times 7\)  to  \(7\).
\[\frac{7\times 7\times 1}{{7}^{v}\times 28}\]
Simplify  \(7\times 7\)  to  \(49\).
\[\frac{49\times 1}{{7}^{v}\times 28}\]
Simplify  \(49\times 1\)  to  \(49\).
\[\frac{49}{{7}^{v}\times 28}\]
Regroup terms.
\[\frac{49}{28\times {7}^{v}}\]
Simplify.
\[\frac{7}{4\times {7}^{v}}\]