$$\frac{1}{(x-3)(x+2)}+\frac{3}{(x+2)(y-2)}+\frac{2}{(x-3)(x-4)}$$
$\frac{3\left(x^{2}+xy-9x+12\right)}{\left(x-4\right)\left(x-3\right)\left(y-2\right)\left(x+2\right)}$
$\frac{3\left(x^{2}+xy-9x+12\right)}{\left(x-4\right)\left(x-3\right)\left(y-2\right)\left(x+2\right)}$
