1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 1 } { \sqrt { 3 } } + \sqrt { 3 } + \frac { \sqrt { 3 } } { 2 }$$

$\frac{11\sqrt{3}}{6}\approx 3.175426481$

Rationalize the denominator of $\frac{1}{\sqrt{3}}$ by multiplying numerator and denominator by $\sqrt{3}$.

$$\frac{\sqrt{3}}{\left(\sqrt{3}\right)^{2}}+\sqrt{3}+\frac{\sqrt{3}}{2}$$

The square of $\sqrt{3}$ is $3$.

$$\frac{\sqrt{3}}{3}+\sqrt{3}+\frac{\sqrt{3}}{2}$$

Combine $\frac{\sqrt{3}}{3}$ and $\sqrt{3}$ to get $\frac{4}{3}\sqrt{3}$.

$$\frac{4}{3}\sqrt{3}+\frac{\sqrt{3}}{2}$$

Combine $\frac{4}{3}\sqrt{3}$ and $\frac{\sqrt{3}}{2}$ to get $\frac{11}{6}\sqrt{3}$.

$$\frac{11}{6}\sqrt{3}$$